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(comprehension is given in image)then find out the following:
1.the value of refractive index of prism used ?
2.the value of i? in degrees ?
Asked by sarveshvibrantacademy | 16 May, 2019, 11:40: AM
Expert Answer
Angle of deviation δ = ( i1 + i2 ) - (r1 + r2 ) ....................(1)
where i1 and i2 are the angle of incidence and angle of emergence when a light ray is undergoing refraction through prism.
r1 is the angle of refraction and r2 is the angle of incidence on opposite side of prism.
Angle of prism A = (r1 + r2 ) .........................(2)
for mimimum deviation δm , we have i1 = i2 = i .......................(3)
using the above relations, we have δm = 2i - A or 60 = 120 - A or A = 60°
refractive index μ =
To get value of i1 we use eqn.(1):- we have, 70 = (40+i1 ) - 60 or i1 = 90°
Answered by Thiyagarajan K | 16 May, 2019, 12:19: PM
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