Request a call back

Complex nos
Asked by | 10 Apr, 2010, 01:51: PM

Dear Student,

Let the center of the circle which touches both circles |z-z1|=a and |z-z2|=b be z0.Let the radius of this circle be r. So the equation of this circle becomes |z-z0|=r.

Now as this circle touches |z-z1|=a, therefore z1 is at a distance of (r+a) from z0.

=> |z0-z1|=a+r               (1)

Similarly, as this circle also touches |z-z2|=b, therefore z2 is at a distance of (r+b) from z0.

=> |z0-z2|=b+r               (2)

Subtracting (2) from (1), we get

|z0-z1| - |z0-z2| = a - b

Since z0 is a variable point, replace it by z and replace (a-b) by k.

=> |z-z1| - |z-z2| = k

This is a standard equation for a hyperbola. therefore, the locus of the centre of the circle which touches the given two circles is a hyperbola.

So, the correct answer is option (c).

Regards Topperlearning.

Answered by | 28 Apr, 2010, 03:26: PM

## Application Videos

CBSE 12-science - Maths
Asked by iasaspirant20s | 09 Oct, 2022, 02:31: PM
CBSE 12-science - Maths
Asked by Raunaksingh4742 | 25 Aug, 2022, 12:31: AM
CBSE 12-science - Maths
Asked by devilkano80 | 07 Jul, 2022, 01:45: PM
CBSE 12-science - Maths
CBSE 12-science - Maths
Asked by saisidh05 | 04 Jul, 2022, 03:04: PM
CBSE 12-science - Maths