Combinations

Asked by  | 30th Nov, 2009, 06:37: PM

Expert Answer:

nC1+nC2+nC3+nC4......+nCn=225

we know that  using binomial (1+1)n   =  nC0 +  nC1+nC2+nC3+nC4......+nCn

 nC0 +  nC1+nC2+nC3+nC4......+nCn  = 2n 

nC1+nC2+nC3+nC4......+nCn  = 2n -1

nC1+nC2+nC3+nC4......+nCn = 225

so 2= 226

n = log (226)/log 2

here n is not coming to be a natural number so check the question from the source and revert

Answered by  | 1st Dec, 2009, 10:53: AM

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