Combinations
Asked by
| 1st Dec, 2009,
12:36: PM
Expert Answer:
If he borrows chemistry I then for the remaining two books out of 7 = 7C2 = 7!/(2!5!) = 21 ways
and if he don't borrow chemistry I then, he'll not borrow chemistry II,
The combinations are 6C3 = 6!/(3!3!) = 20
Total 41 different ways he can borrow three books.
Regards,
Team,
TopperLearning.
Answered by
| 1st Dec, 2009,
11:02: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change