circumference of base of a cylinder is 132cm. the sum of radius and height of the cylinder is 41cm. find the cost of polishing the outer surface of cylinder at rate of RS10 per square metre.

Asked by  | 6th Feb, 2014, 08:57: PM

Expert Answer:

Circumference of the base of a cylinder is 2 pi r equals 132 space c m space left parenthesis g i v e n right parenthesis
 
Thus, r equals fraction numerator 132 over denominator 2 pi end fraction equals 66 over pi
 
Also, given that, r plus h equals 41 rightwards double arrow h equals 41 minus r rightwards double arrow h equals 41 minus 66 over pi
 
The curved surface area of a cylinder is given by, C S A equals 2 pi r h equals 2 pi cross times 66 over pi cross times open parentheses 41 minus 66 over pi close parentheses equals 132 open parentheses 41 minus 66 over pi close parentheses space c m squared
That is,
C S A equals 5412 minus 2773.1 space c m squared equals 2638.88 space cross times 1 over 10000 space m squared equals 0.2639 space m squared
 
Cost of polishing the outer surface per square meter is Rs.10.
 
Thus the cost of polishing the outer surface of cylinder = 0.2639 cross times 10 equals R s.2.639

Answered by  | 7th Feb, 2014, 09:50: AM

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