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CBSE Class 10 Answered

Circuit
Asked by baidshryans | 26 Feb, 2009, 11:58: PM
Expert Answer

Since the resistances ,R1=4ohm and R2 = 6ohm ,are connected in parallel,
The net resistance (R')=>   1/R' = 1/R1 + 1/R2 => R' = 4x6 / (4+6) = 2.4ohm

The cells are connected in series .Therefore their voltages gets added = 2+2 = 4V

a) The ammeter gives the value of the current (I) in the circuit .I = Voltage / resistance = 4V / 2.4ohm = 1.66A

 

b) Power = Voltage x current = 4V x  1.66 = 6.64V

Answered by | 27 Feb, 2009, 12:10: AM
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