Asked by hemant2020 | 4th Feb, 2010, 09:11: PM

Expert Answer:

let ABC be the right triangle right angled at B.

let  O be the mid pt of the hypo. AC.

thru' O draw line parallel to BC meeting AB on P.


AP=PB..  conv of mid pt theorem

Angle OPA=OPB=90 each as line OP II BC and angle B is 90 degrees.

now consider triangles OAP and OBP,

we have


OP=OP.. common

angel OPA=OPB.. each 90 degrees.

 so the triangles are cong.... RHS rule.


but OA=OC.. since O  is mid pt of AC

so we get


 Hence proved.

Answered by  | 4th Feb, 2010, 11:32: PM

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