Asked by hemant2020 | 4th Feb, 2010, 09:11: PM
let ABC be the right triangle right angled at B.
let O be the mid pt of the hypo. AC.
thru' O draw line parallel to BC meeting AB on P.
AP=PB.. conv of mid pt theorem
Angle OPA=OPB=90 each as line OP II BC and angle B is 90 degrees.
now consider triangles OAP and OBP,
angel OPA=OPB.. each 90 degrees.
so the triangles are cong.... RHS rule.
but OA=OC.. since O is mid pt of AC
so we get
Answered by | 4th Feb, 2010, 11:32: PM
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