CBSE Class 10 Answered
CIRCLES
Asked by akhileshnarayanan | 06 Feb, 2010, 09:51: PM
Expert Answer
We need to show that BOA + APB = 180,
In quadrilateral OAPB,
BOA + APB + OAP + OBP = 360
But OAP = OBP = 90 ...................... since the radius at the point of contact of a tangent is perpendicular to
the tangent at the point of contact.
BOA + APB + 90 + 90 = 360
BOA + APB = 180
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Team,
TopperLearning.
Answered by | 07 Feb, 2010, 10:04: AM
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