Circles

Asked by  | 26th Feb, 2009, 02:27: PM

Expert Answer:

OP2= PT2+ r2     (By pythagora's theorem)

PT2 = OP2-r2

OP2= OD2 + PD2

       = r2- x2 + (PA + x)2

PT2 = r2- x2 + (PA + x)2-r2

        = PA2 +2PA.x

        = PA (PA + 2x)

2x = AB

PT2 = PA. (PA+AB)

       = PA.PB

Hence Proved.

Answered by  | 27th Feb, 2009, 09:38: AM

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