Asked by  | 12th Oct, 2008, 01:12: PM

Expert Answer:

Let O be the centre of the circles . Let P be the point of tangency , i.e the point at  which

the chord of the larger circle which touches  the smaller circle. Let K and K'be the points at which the chord touches the outer circle.

*Answer Description:

Now OPK is a right triangle

PK2  = 32  + 52   = 9 + 25 = 34

Triangles OPK and OPK'are congruent (RHS)

Pk = PK'

So KK'= 2 x 34  = 68

Answered by  | 12th Oct, 2008, 10:43: PM

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