Asked by | 12th Oct, 2008, 01:12: PM
Let O be the centre of the circles . Let P be the point of tangency , i.e the point at which
the chord of the larger circle which touches the smaller circle. Let K and K'be the points at which the chord touches the outer circle.
Now OPK is a right triangle
PK2 = 32 + 52 = 9 + 25 = 34
Triangles OPK and OPK'are congruent (RHS)
Pk = PK'
So KK'= 2 x 34 = 68
Answered by | 12th Oct, 2008, 10:43: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number