CIRCLES-cyclic Quadrilaterals

Asked by jal.panchal | 11th Mar, 2008, 09:39: PM

Expert Answer:

Let ABCD be a cylclic quadrilateral.  AEB, BFC, CGD and DHA are in respective segments.
               of AB, BC, CD and DA.

 Join the  diagonal AC.
              H + ACD = 180  ........(i)   (opp. angles of a cyclic quad.)
               E +  ACB = 180 .........(ii)
               F + BAC = 180  ........(iii)
                G + CAD = 180  ........(iv)
               adding (i), (ii), (iii) and (iv) gives us the solution
              

Answered by  | 15th Mar, 2008, 12:00: PM

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