Asked by jal.panchal | 11th Mar, 2008, 09:39: PM
Let ABCD be a cylclic quadrilateral. AEB, BFC, CGD and DHA are in respective segments.
of AB, BC, CD and DA.
Join the diagonal AC.
H + ACD = 180 ........(i) (opp. angles of a cyclic quad.)
E + ACB = 180 .........(ii)
F + BAC = 180 ........(iii)
G + CAD = 180 ........(iv)
adding (i), (ii), (iii) and (iv) gives us the solution
Answered by | 15th Mar, 2008, 12:00: PM
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