Circle

Asked by thebluebloo | 16th Dec, 2008, 03:17: PM

Expert Answer:

since line passes through fourth quadrent so center of circle must be in fourth quad. so center of circle is (h ,-h)

 and radius is h.

the eqn. of circle touches axes is (x - h )2  + (y + h)2 = h2

since point (h ,-h) lie on line x - 2y = 3 so  h - 2(-h) = 3  ===>h =1

so eqn of circle is (x - 1)2 +(y +1)2 = 1

Answered by  | 16th Dec, 2008, 07:12: PM

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