Circle
Asked by thebluebloo | 16th Dec, 2008, 03:17: PM
since line passes through fourth quadrent so center of circle must be in fourth quad. so center of circle is (h ,-h)
and radius is h.
the eqn. of circle touches axes is (x - h )2 + (y + h)2 = h2
since point (h ,-h) lie on line x - 2y = 3 so h - 2(-h) = 3 ===>h =1
so eqn of circle is (x - 1)2 +(y +1)2 = 1
Answered by | 16th Dec, 2008, 07:12: PM
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