Circle

Asked by thebluebloo | 16th Dec, 2008, 03:13: PM

Expert Answer:

as from general eqn of cicle x2 +y2 +2gx +2fy +c =0   center (-g,-f) radius = (g2+ f2 -c)                                                                    intercept on x axis = 2(g2-c) ; intercept on y axis = 2(f2-c)

an intercept of 8 units===>2(g2-c) =8..........(1)

As circles touching y-axis at (0,3) so y co-ordinate of the center is 3===> - f = -3 ===>f=3;                                         and  intercept on y axis = 0 ===>f2=c.==> c = 9

so by solving 1 we get g,f,c as  (-5 , 3 , 9)respectively .putting in general eqn. we get required eqn.

x2 +y2 - 10x + 6y +9 = 0

Answered by  | 16th Dec, 2008, 08:16: PM

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