CBSE Class 10 Answered
Chords AB and CD of a circle intersect inside the circle at point E. If AE = 4, EB = 10, CE = 8, find ED.
(A) 7 (B) 5 (C) 8 (D) 9
Asked by paresh0311 | 18 Mar, 2023, 10:58: PM
Expert Answer
Chords AB and CD of a circle intersect inside the circle at point E
AE = 4, EB = 10, CE = 8
To find: ED
According to theorem Internal division of chords,
AE × EB = CE × ED
4 × 10 = 8 × ED
ED = 5
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