Can you please tell me how the current flowing through all the resistors connected in series is the same?
How is the total resistance in parallel calculated as 1/Req = 1/R1+ 1/R2 +1/R3......?
Asked by joshiraghavendra53 | 6th Jul, 2014, 07:25: PM
When two or more resistors are joined from end to end, then the resistances are connected in series. In such a case current has a single path for its flow.
i.e The, resistors in series have a common current flowing through them as the current that flows through one resistor must also flow through the others as it can only take one path.Hence same current passes through each resistors.
The potential difference across the entire circuit is equal to the sum of potential differences across all the individual resistors.V =V 1+V 2+V 3+.......
When two or more resistors are joined with same end joined together, then the resistances are connected in parallel.
The potential difference in parallel connection remains same across all the resistors and is equal to the potential difference across the terminals of the battery.
The current is the sum of the currents across all the individual resistors. ie
Answered by Jyothi Nair | 7th Jul, 2014, 09:47: AM
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