Can You please show the solution of the following sums :-

 

1. (a²-1)(b²-1)+4ab
2. x⁴+x²+1

Assuming that the question asks to factorise the given expressions, the explanation is as follows:

 

1. (a²-1)(b²-1)+4ab = a²b²-a²-b²+1+4ab= a²b²-a²-b²+1+2ab+2ab

Rearranging the terms, we get 

(a²b²+2ab+1)-(a²+b²-2ab)

=(ab+1)² - (a-b)²

=(ab+1+a-b)(ab+1-(a-b))

=(ab+1+a-b)(ab+1-a+b)

 

2. x⁴+x²+1 =  x⁴+2x²-x²+1

Rearranging the terms, we get

(x⁴+2x²+1) - x²

=(x²+1)² - x²

=(x²+1+x)(x²+1-x)