Can we do this like as follows cot2cot12cot22cot32cot42cot45cot48cot58cot68cot78cot88 =(cot2cot88)(cot12cot78)(cot22cot68)(cot32cot58)(cot42cot48)cot45 =(cot2Tan2)(cot12Tan12)(cot22tan22)(cot32tan32)(cot42tan42)cot45 =(1)(1)(1)(1)(1)cot45 =1 x 1 =1

Asked by RAHUL rd | 10th Sep, 2014, 02:21: PM

Expert Answer:

C o n s i d e r space t h e space g i v e n space e x p r e s s i o n : c o t 2 cross times c o t 12 cross times c o t 22 cross times c o t 32 cross times c o t 42 cross times c o t 45 cross times c o t 48 cross times c o t space 58 cross times c o t 68 cross times c o t 78 cross times c o t 88 equals c o t 2 cross times c o t 12 cross times c o t 22 cross times c o t 32 cross times c o t 42 cross times c o t 45 cross times c o t open parentheses 90 minus 42 close parentheses cross times c o t open parentheses 90 minus 32 close parentheses cross times c o t open parentheses 90 minus 22 close parentheses cross times c o t open parentheses 90 minus 12 close parentheses cross times c o t open parentheses 90 minus 2 close parentheses equals c o t 2 cross times c o t 12 cross times c o t 22 cross times c o t 32 cross times c o t 42 cross times c o t 45 cross times tan 42 cross times tan 32 cross times tan 22 cross times tan 12 cross times tan 2 equals c o t 2 cross times tan 2 cross times c o t 12 cross times tan 12 cross times c o t 22 cross times tan 22 cross times c o t 32 cross times tan 32 cross times c o t 42 cross times tan 42 cross times c o t 45 equals c o t 2 cross times fraction numerator 1 over denominator c o t 2 end fraction cross times c o t 12 cross times fraction numerator 1 over denominator c o t 12 end fraction cross times c o t 22 cross times fraction numerator 1 over denominator c o t 22 end fraction cross times c o t 32 cross times fraction numerator 1 over denominator tan 32 end fraction cross times c o t 42 cross times fraction numerator 1 over denominator c o t 42 end fraction cross times c o t 45 equals 1 cross times 1 cross times 1 cross times 1 cross times 1 cross times 1 equals 1

Answered by Vimala Ramamurthy | 10th Sep, 2014, 03:41: PM

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