can u solve

Asked by  | 5th May, 2009, 10:31: PM

Expert Answer:


From the question we gather that the required number will be 17 less than the smallest common multiple (LCM)of 520 and 468.

The L.C.M of the given numbers =product of the numbers /hcf=4680

So we need to find the number which is less than 4680 and less by 17.

So the reqd number is 4680-17=4663


If we add 17 to 4663 ,

 we get,

 4680 ,

 which is exactly divisible by 520 and 468

Answered by  | 7th May, 2009, 02:41: PM

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