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Can u pls give simplest way to solve solution to 3-d right triangles(trignometric ratios)?
Asked by | 15 Feb, 2009, 03:55: PM

Just remember that sin 30=1/2

then draw a right triangle , with one of the acute angles as 30 degrees.So the other acute angle has to be 60 degrees.

In the right triangle find the third side using pythagoras' theorem( two of the sides are 1x and 2x as sin 30 is 1/2)

the third side will come out to be square root 3 multiplied by x.

So now you can find the values for cos30, sin60, and tan 30, tan 60 easily looking at the triangle sides.

In the similar way, for 45 degrees, you can draw an iscoceles  right triangle .

So each of the acute angles willbecome 45 degrees.

So two sides have to be same .

Take them as x and x , then the third side will be root 2 multiplied by x.

Using the three sides you can easily find  t-ratios for 45 degrees.

If you want to know anything more, do get back to us.

Answered by | 16 Feb, 2009, 10:22: AM

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