Can orbitals 6f,6g,7d,7f exist?Give reason for your answer.
Asked by | 15th Sep, 2011, 08:24: AM
Expert Answer:
yes these orbitals can exist. Rules are algorithms, by which we generate possible quantum numbers. The lowest value of n is 1 (NOT zero). For n = 1, the only possible value for quantum number l is 0, and m = 0. Each set of quantum numbers is called a state. Thus, for n = 1, there is only one state (1,0,0). The states are represented by symbols, and special symbols have been used to represent the quantum number l as follows:
l = 0, 1, 2, 3, 4, ...
symbol = s, p, d, f, g, ...
The three quantum numbers (q.n.) n, l, m follow the rules:
for the principal q.n. n
azimuthal q.n. l = 0, 1, 2, ..., n-1
magnetic q.n. m = -l, -(l-1), ..., (l-1), l
So, these orbitals are possible.
l = 0, 1, 2, 3, 4, ... symbol = s, p, d, f, g, ...
The three quantum numbers (q.n.) n, l, m follow the rules:
for the principal q.n. n azimuthal q.n. l = 0, 1, 2, ..., n-1 magnetic q.n. m = -l, -(l-1), ..., (l-1), l
So, these orbitals are possible.
Answered by | 15th Sep, 2011, 08:58: AM
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