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CBSE Class 9 Answered

CAN I GET ATLEAST 5 QUESTIONS BASED ON THE BELOW CRITERIA:
 
 
EACH SIDE OF A CUBE IS INCREASED BY 50%. FIND THE PERCENTAGE INCREASE IN THE SURFACE AREA OF THE CUBE.
Asked by mishra.25.reena | 12 Oct, 2015, 04:11: PM
answered-by-expert Expert Answer
begin mathsize 14px style Let space the space side space of space the space cube space equals space straight x space cm space Length space of space the space side space after space increase space by space 50 percent sign equals space straight x space plus open parentheses space straight x space cross times 50 over 100 close parentheses equals straight x space plus space straight x over 2 space equals space fraction numerator 3 straight x over denominator 2 end fraction space cm Total space surface space area space of space cube space equals space 6 straight x squared space... open parentheses formula close parentheses Total space surface space Area space of space original space cube space equals space 6 straight x squared space TSA space of space new space cube space after space increase space in space side space length space equals space 6 cross times open parentheses fraction numerator 3 straight x over denominator 2 end fraction close parentheses squared equals 6 cross times fraction numerator 9 straight x squared over denominator 4 end fraction equals fraction numerator 27 straight x squared over denominator 2 end fraction therefore Increase space in space surface space area space equals fraction numerator 27 straight x squared over denominator 2 end fraction minus space 6 straight x squared equals 7.5 straight x squared therefore Percentage space increase space in space surface space area space equals space fraction numerator 7.5 over denominator 6 end fraction cross times 100 space equals space 125 therefore Percentage space increase space in space surface space area space equals space 125 percent sign end style
 
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