CBSE Class 11-science Answered
Calculate the weight of CaO required to remove Hardness of 10^6 L of water containing 1.62g of Ca(HCO3)2 in 1l.
Asked by pb_ckt | 29 May, 2019, 11:38: PM
Expert Answer
Given:
Volume of water = 106 L
Weight of Ca(HCO3)2 = 1.62 gm
The reaction equation is written as,
Eq. of Ca(HCO3)2 present in hard water is
So the eq of CaO required to remove hardness of 1 L H2O is 0.02
Eq of CaO required to remove hardness of 106 L is 0.02 × 106
= 2 × 104
Mass of CaO =
The weight of CaO required to remove hardness is 560 kg.
Answered by Varsha | 30 May, 2019, 12:02: PM
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