CBSE Class 11-science Answered
Calculate the wave number for longest wavelength transition in the balmer series of atomic hydrogen.
Asked by Bidyashree Rout | 04 Oct, 2013, 07:10: PM
Expert Answer
For the Balmer series, ni = 2. Thus, the expression of wavenumber is given by,
Wave number is inversely proportional to wavelength of transition. Hence, for the longest wavelength transition, has to be the smallest.
For to be minimum, nf should be minimum. For the Balmer series, a transition from ni = 2 to nf = 3 is allowed. Hence, taking nf = 3, we get:
= 1.5236 × 106 m1
Answered by | 04 Oct, 2013, 09:25: PM
Application Videos
Concept Videos
CBSE 11-science - Chemistry
Asked by ammu32811 | 20 Feb, 2024, 08:58: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ee7511641 | 13 Jan, 2024, 03:37: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by kv3582976 | 11 Oct, 2023, 06:57: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by o230397 | 23 Sep, 2023, 02:48: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by shrreya27harshitha | 17 Jul, 2022, 04:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by habibakhatoon112 | 15 Jul, 2022, 09:14: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by deba.biswas561 | 14 Jun, 2022, 08:07: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by advssdrall | 12 Jan, 2022, 05:12: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ks1221516 | 14 Nov, 2021, 06:46: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by akankhyapradhan123 | 22 Oct, 2021, 07:29: PM
ANSWERED BY EXPERT