Calculate the wave number and wavelength of the first two line in a pascal series of hydrogen spectrum

Asked by hemanttkumarr | 24th Jul, 2017, 08:26: PM

Expert Answer:

Dear hemanttkumarr@yahoo.com

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For space Paschen space series comma space straight n subscript 1 space equals space 3 bold For bold space bold 1 bold st bold space bold line bold colon 1 over straight lambda space equals space straight R subscript straight H space open square brackets fraction numerator 1 over denominator left parenthesis straight n subscript 1 right parenthesis squared end fraction space minus space fraction numerator 1 over denominator left parenthesis straight n subscript 2 right parenthesis squared end fraction close square brackets space space equals space 1.097 space cross times space 10 to the power of 7 space open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis squared end fraction space minus space fraction numerator 1 over denominator left parenthesis 4 right parenthesis squared end fraction close square brackets space equals space 5.33 space cross times space 10 to the power of 5 space straight m to the power of negative 1 end exponent straight lambda space equals space bold 18752 bold space bold A with bold ring operator on top  bold For bold space bold 2 bold nd bold space bold line bold colon  1 over straight lambda space equals space straight R subscript straight H space open square brackets fraction numerator 1 over denominator left parenthesis straight n subscript 1 right parenthesis squared end fraction space minus space fraction numerator 1 over denominator left parenthesis straight n subscript 2 right parenthesis squared end fraction close square brackets space space equals space 1.097 space cross times space 10 to the power of 7 space open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis squared end fraction space minus space fraction numerator 1 over denominator left parenthesis 5 right parenthesis squared end fraction close square brackets space equals space 7.11 space cross times space 10 to the power of 5 space straight m to the power of negative 1 end exponent straight lambda space equals space bold 12820 bold space bold A with bold ring operator on top


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Answered by Arvind Diwale | 25th Jul, 2017, 09:32: AM