Calculate the pH.

Asked by  | 26th Jan, 2009, 03:17: PM

Expert Answer:

pH=-log[H+]

pOH=-log[OH-]

Therefore pOH=-log[4 X 10-11]

Therefore pOH= -log 4+11 log 10

Therefore pOH=0.602 + 11= 10.398

pH+pOH=14

Therefore pH=14-10.398= 3.602

Answered by  | 28th Jan, 2009, 04:02: PM

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