Calculate the number of sulphate ions in 39.2 g of chromium sulphate.

Asked by Prince Sonu | 19th Apr, 2013, 12:10: PM

Expert Answer:

Gram molecular mass of Cr2(SO4)3 = 392.6 g

No. of moles in 39.2 g of Cr2(SO4)3 = 39.2/392.6 = 0.1 mol 

1 mol of Cr2(SO4)3 contains = 3 x 6.023 x 1023 sulphate ions

So, 0.1 mol of Cr2(SO4)3 will contain = 0.1 x 3 x 6.023 x 1023 = 1.8069 x 1023 sulphate ions

Answered by  | 23rd Apr, 2013, 02:35: PM

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