Calculate the number of sulphate ions in 39.2 g of chromium sulphate.
Asked by Prince Sonu | 19th Apr, 2013, 12:10: PM
Expert Answer:
Gram molecular mass of Cr2(SO4)3 = 392.6 g
No. of moles in 39.2 g of Cr2(SO4)3 = 39.2/392.6 = 0.1 mol
1 mol of Cr2(SO4)3 contains = 3 x 6.023 x 1023 sulphate ions
So, 0.1 mol of Cr2(SO4)3 will contain = 0.1 x 3 x 6.023 x 1023 = 1.8069 x 1023 sulphate ions
Gram molecular mass of Cr2(SO4)3 = 392.6 g
No. of moles in 39.2 g of Cr2(SO4)3 = 39.2/392.6 = 0.1 mol
1 mol of Cr2(SO4)3 contains = 3 x 6.023 x 1023 sulphate ions
So, 0.1 mol of Cr2(SO4)3 will contain = 0.1 x 3 x 6.023 x 1023 = 1.8069 x 1023 sulphate ions
Answered by | 23rd Apr, 2013, 02:35: PM
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