Calculate the number of protons, electrons, and neutrons present in each component of 5.85g of NaCl. ( use N = 6 x 10^23)
Asked by Theodosia Lourdes | 19th Apr, 2011, 12:41: AM
Molecular weight of NaCl = 23 + 35.5 = 58.5 gram.
So, in 5.85 g of NaCl there will be number of moles of NaCl = 58.5/5.85 =10 moles
In 10 moles of NaCl there will be 10 X 6.022 X 1023 molecules of NaCl.
In 1 molecule of NaCl there are total electron = (11 X 1) + (17X 1) = 28
So, in 10 X 6.022 X 1023 molecules of NaCl, total electrons =10 X 6.022 X 1023 X 28 = 1686.44 X 1023
or 16.86 X 1025
Similarly total no. of protons and neutrons can also be calculated.
Answered by | 20th Apr, 2011, 09:50: AM
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