Calculate the number of protons, electrons, and neutrons present in each component of 5.85g of NaCl. ( use N = 6 x 10^23)

Asked by Theodosia Lourdes | 19th Apr, 2011, 12:41: AM

Expert Answer:

Molecular weight of NaCl = 23 + 35.5 = 58.5 gram.
 
So, in 5.85 g of NaCl there will be number of moles of NaCl = 58.5/5.85 =10 moles 
 
In 10 moles of NaCl there will be 10 X 6.022 X 1023 molecules of NaCl.
 
In 1 molecule of NaCl there are total electron = (11 X 1) + (17X 1) = 28
 
So, in 10 X 6.022 X 1023 molecules of NaCl, total electrons =10 X 6.022 X 1023 X 28 = 1686.44 X 1023
or 16.86 X 1025
 
Similarly total no. of protons and neutrons can also be calculated.

Answered by  | 20th Apr, 2011, 09:50: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.