calculate the number of oxygen atoms present in 0.75 moles of SO2.
Asked by araima2001 | 29th May, 2014, 11:38: AM
Expert Answer:
1 mole of SO2 contains 1 mole of S and 2 moles of oxygen atoms.
Hence 0.75 mole of SO2 x2/1 = 1.5 mol O atoms
1.5 mol O atoms x 6.02 x 1023 atoms / 1 mol
= 9.0345 x 1023 atoms of Oxygen
1 mole of SO2 contains 1 mole of S and 2 moles of oxygen atoms.
Hence 0.75 mole of SO2 x2/1 = 1.5 mol O atoms
1.5 mol O atoms x 6.02 x 1023 atoms / 1 mol
= 9.0345 x 1023 atoms of Oxygen
Answered by Prachi Sawant | 29th May, 2014, 12:15: PM
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