Calculate the number of oxygen atoms in 0.2 mole of Na2Co3.10H2O .
Asked by | 24th May, 2013, 12:28: AM
Expert Answer:
1 mol of Na2CO3.10H2O contains 10+3 = 13 mole O atoms f(rom the formula)
we have 0.2 moles of Na2CO3.10H2O
So, we will have 13 x 0.2 = 2.6 mol O atoms
Since, 1 mole O atoms = 6.022 x 1023 atoms
2.6 mol O atoms = 2.6 x 6.022 x 1023 = 1.57 x 1024 O atoms.
1 mol of Na2CO3.10H2O contains 10+3 = 13 mole O atoms f(rom the formula)
we have 0.2 moles of Na2CO3.10H2O
So, we will have 13 x 0.2 = 2.6 mol O atoms
Since, 1 mole O atoms = 6.022 x 1023 atoms
2.6 mol O atoms = 2.6 x 6.022 x 1023 = 1.57 x 1024 O atoms.
Answered by | 24th May, 2013, 09:59: AM
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