CBSE Class 11-science Answered

Calculate the number of moles of $CO subscript 2$ which contain 8.00 grams of $straight O subscript 2$ .

Asked by aashimegh | 28 Aug, 2019, 05:28: PM

Expert Answer

1 molecule of CO₂ will have= 32 g of O₂

6.022 cross times 10 to the power of 23 space m o l e c u l e s space o f space C O subscript 2 equals space 1 space m o l e space o f space C O subscript 2 1 space m o l e c u l e space o f space C O subscript 2 equals fraction numerator 1 over denominator 6.022 cross times 10 to the power of 23 end fraction m o l e s 32 space g r a m space o f space O subscript 2 space end subscript space p r e s e n t space i n space equals fraction numerator 1 over denominator 6.022 cross times 10 to the power of 23 end fraction m o l e s space o f space C O subscript 2 8 space g r a m space o f space O subscript 2 space o f space O subscript 2 space w i l l space b e space p r e s e n t space i n equals fraction numerator 1 over denominator 6.022 cross times 10 to the power of 23 end fraction cross times 8 over 32 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 1 over denominator 24.088 end fraction cross times 10 to the power of negative 23 end exponent space space m o l e s space o f space C O subscript 2

Answered by Ravi | 29 Aug, 2019, 11:17: AM

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