calculate the number of aluminum ions present in 0.051g of aluminium oxide?{please tell me the answers with step}

Asked by Anandakrishnan . | 21st Jan, 2011, 12:00: AM

Expert Answer:

Dear Student
 
Molecular Wt of Al2O3 is = 101.96 
So, in 101.96 g = 1 mol of Al2O3  = 2 mol Al3+ 
 
So, in 0.051 g there will be number of moles of Al2O3 = 0.051/101.9614 = 0.0005 mol
1mol Al2O3 contains 2mol Al.

So, Mol Al = 0.0005 x 2 = 0.001 mol Al

1mol Al3+ contains = 6.022 x 1023 ions. 

0.001mol contains = 6.022 x 1023  x 0.001 = 6.022 x 1020 ions
 
 
 
We hope that clarifies your query.
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Answered by  | 22nd Jan, 2011, 09:36: AM

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