calculate the number of aluminum ions present in 0.051g of aluminium oxide?{please tell me the answers with step}

Dear Student

 

Molecular Wt of Al₂O₃ is = 101.96 

So, in 101.96 g = 1 mol of Al₂O₃  = 2 mol Al³⁺ 

 

So, in 0.051 g there will be number of moles of Al₂O_{3 =} 0.051/101.9614 = 0.0005 mol

1mol Al2O3 contains 2mol Al.

So, Mol Al = 0.0005 x 2 = 0.001 mol Al

1mol Al³⁺ contains = 6.022 x 10²³ ions. 

0.001mol contains = 6.022 x 10²³  x 0.001 = 6.022 x 10²⁰ ions

 

 

 

We hope that clarifies your query.

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