Calculate the no. of particles present in 52 g of helium?

Asked by nisha_vini29 | 13th Nov, 2017, 12:10: PM

Expert Answer:

No. space of space particles space in space 52 space straight g space of space helium comma
No. space of space moles equals 52 over 4
space space space space space space space space space space space space space space space space space space space space equals 13
As space 1 space mole space of space sustance space contains space 6.022 cross times 10 to the power of 23 space particles
therefore 13 space moles space of space He space will space contain
13 cross times 6.022 cross times 10 to the power of 23 equals 7.82 cross times 10 to the power of 24 space end exponent particles

Answered by Varsha | 13th Nov, 2017, 01:02: PM