CBSE Class 11-science Answered
calculate the no. of molecule present in 34.2 gram of canesugar
Asked by Abhinav Maurya | 09 Apr, 2014, 07:20: PM
Expert Answer
Molecular mass of cane sugar (C6H22O11) = 342g
1 mole of C6H22O11 = 342g
342 g of cane sugar contain 6.022 x 1023 molecules
34.2 g of cane sugar will contain = 6.022 x 1022 molecules
Answered by | 10 Apr, 2014, 09:55: AM
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