calculate the no. of molecule present in 34.2 gram of canesugar

Asked by Abhinav Maurya | 9th Apr, 2014, 07:20: PM

Expert Answer:

Molecular mass of cane sugar (C6H22O11) = 342g

 1 mole of  C6H22O11  = 342g

 342 g of cane sugar contain 6.022 x 1023 molecules

34.2 g of cane sugar will contain       = 6.022 x 1022  molecules

 

Answered by  | 10th Apr, 2014, 09:55: AM

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