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CBSE Class 11-science Answered

Calculate the mole fraction of solute and solvent in 20% of w/v% of Naoh (aq) given density as 1.25g/ml?

Asked by manuasha93 | 23 May, 2021, 09:14: PM
Expert Answer
Percentage weight by volume is given=20%
Which means 20 gram of solute is present in 100 ml of solution.
 
If we are taking 100 ml of solution.
 
D e n s i t y space o f space S o l u t i o n equals fraction numerator M a s s space o f space S o l u t i o n over denominator V o l u m e space o f space S o l u t i o n end fraction
1.25 space g divided by m l equals fraction numerator M a s s space o f space s o l u t i o n over denominator 100 end fraction
M a s s space o f space S o l u t i o n equals 125 space g

M a s s space o f space S o l u t i o n equals 125 cross times 1.25
M a s s space o f space S o l u t i o n equals 125 cross times 1.25
space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 156.25 space g space

M a s s space o f space S o l v e n t equals 156.25 minus 20 equals 136.25 space g space

M o l e s space o f space S o l u t e left parenthesis N a O H right parenthesis equals fraction numerator M a s s space o f space S o l u t e over denominator M o l a r space m a s s space o f space S o l u t e end fraction equals 20 over 40 equals 0.5 space m o l e s

M o l e s space o f space S o l v e n t left parenthesis H subscript 2 O right parenthesis equals fraction numerator 136.25 over denominator 18 end fraction equals 7.569 space m o l e s
Answered by Ravi | 26 May, 2021, 06:34: PM
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