Calculate the molarity of 30 mL of 0.5 M H2SO4 diluted to 500 mL.

Asked by bharathmazumdar | 17th Jun, 2013, 07:38: PM

Expert Answer:

Volume of H2SO4 (V1) = 30 ml)

Diluted volume of H2SO4 (V2) = 500 ml

Number of moles present in 1000 mL of 0.5 M H2SO4 = 0.5 mol

Initial molarity M1= 0.5 M 

We have to find M2 (molarity of 500 ml solution)

M2V2 = M1V1

M2  × 500  = 0.5 × 30

M2 = 15/ 500 = 0.03 M

Answered by  | 18th Jun, 2013, 10:18: AM

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