Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

Calculate the molar conductance of 0.01M solution of an electrolyte which has a resistance of 210ohms at 298K. Cell constant is 0.88cm-1 

Asked by mrudulmahadev1311 | 20 Aug, 2019, 08:40: PM
Expert Answer
Given:
 
Resistance = 210 Ω
 
Concentration of solution = 0.1 M
 
Cell constant = 0.88 cm−1 
 
Specific conductance 
 
equals fraction numerator Cell space constant over denominator Resistance end fraction

equals fraction numerator 0.88 over denominator 210 end fraction

space equals 0.00419 space ohm to the power of negative 1 end exponent space cm to the power of negative 1 end exponent
 
Molar conductance 
 
equals Specific space conductance cross times 1000 over straight C

space equals 0.00419 cross times fraction numerator 1000 over denominator 0.01 end fraction

space equals space 419.04 ohm space cm squared space mole to the power of negative 1 end exponent
Answered by Varsha | 21 Aug, 2019, 11:04: AM
JEE main - Chemistry
Asked by bhyogita884 | 12 Jul, 2022, 02:55: AM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by abdulraqeeb437 | 16 Jun, 2022, 08:38: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by mrudulmahadev1311 | 20 Aug, 2019, 08:40: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by vishakhachandan026 | 16 Aug, 2019, 07:47: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by lovemaan5500 | 30 Jan, 2019, 12:01: PM
ANSWERED BY EXPERT
JEE main - Chemistry
Asked by lovemaan5500 | 30 Jan, 2019, 11:59: AM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×