Calculate the molar conductance of 0.01M solution of an electrolyte which has a resistance of 210ohms at 298K. Cell constant is 0.88cm-1 

Asked by mrudulmahadev1311 | 20th Aug, 2019, 08:40: PM

Expert Answer:

Given:
 
Resistance = 210 Ω
 
Concentration of solution = 0.1 M
 
Cell constant = 0.88 cm−1 
 
Specific conductance 
 
equals fraction numerator Cell space constant over denominator Resistance end fraction

equals fraction numerator 0.88 over denominator 210 end fraction

space equals 0.00419 space ohm to the power of negative 1 end exponent space cm to the power of negative 1 end exponent
 
Molar conductance 
 
equals Specific space conductance cross times 1000 over straight C

space equals 0.00419 cross times fraction numerator 1000 over denominator 0.01 end fraction

space equals space 419.04 ohm space cm squared space mole to the power of negative 1 end exponent

Answered by Varsha | 21st Aug, 2019, 11:04: AM

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