Calculate the median of the data.
Asked by | 11th Sep, 2012, 09:15: PM
The gaps between mid values of the intervals are 10 each.
Now, 10/2 = 5.
For the mid value 115, lower class limit = 115 - 5 = 110
And upper limit = 115 + 5 = 120.
Hence, the given table can be reconstructed as
n = 384, n/2 = 192
Median class = 150 - 160,
Lower limit of the median class, l = 150
Frequency of the median class, f = 116
Cumulative frequency of the class interval preceding the median class, cf = 151
Width of each class interval, h = 10.
Answered by | 12th Sep, 2012, 10:41: AM
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