CBSE Class 11-science Answered
Calculate the 
H of the following reaction, which describes the production of coal gas from carbon, given the steps below.
H2O (g)
+
C (s)
CO (g)
+
H2 (g)
Given Steps
H2 (g)
+
1/2 O2 (g)
H2O (g)
H
=
- 242.0 kJ
2CO (g)
2 C (s)
+
O2 (g)
H
=
+ 221.0 kJ
H of the following reaction, which describes the production of coal gas from carbon, given the steps below.
H2O (g)
+
C (s)
CO (g)
+
H2 (g)
Given Steps
H2 (g)
+
1/2 O2 (g)
H2O (g)
H
=
- 242.0 kJ
2CO (g)
2 C (s)
+
O2 (g)
H
=
+ 221.0 kJ
Asked by Topperlearning User | 15 Jun, 2016, 17:35: PM
Expert Answer
1) The overall equation is written above.
Note that the H2O (g) is a reactant and in step #1 it is a product. Thus step one needs to be reversed and the sign of the heat changed.
Note that 1 mole of CO (g) is a product in the overall equation, but 2 moles of CO (g) is a reactant in step 2 . Thus step two needs to be reversed, and divided by two.
Note that 1 mole of CO (g) is a product in the overall equation, but 2 moles of CO (g) is a reactant in step 2 . Thus step two needs to be reversed, and divided by two.
2) Manipulated equations
|
H2O (g)
|
 |
H2 (g)
|
+
|
1/2 O2 (g)
|
 H |
=
|
+ 242.0 kJ
|
|
C (s)
|
+
|
1/2 O2 (g)
|
|
CO (g)
|
H |
=
|
- 110.5 kJ
|
3) Add equations and heats
|
H2O (g)
|
+
|
C (s)
|
+
|
1/2 O2 (g)
|
|
1/2 O2 (g)
|
+
|
H2 (g)
|
+
|
CO (g)
|
H = +131.5 kJ |
Substances in bold above are common and therefore are canceled
Net Equation:
|
H2O (g)
|
+
|
C (s)
|
|
H2 (g)
|
+
|
CO (g)
|
H = +131.5 kJ |
Answered by | 15 Jun, 2016, 19:35: PM
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