CBSE Class 11-science Answered
Calculate the emperical formula of the compound formed when 7.30 g of iron powder reacts completely with 6.30 g of powdered sulphur . (At mass Fe=55.55;S=32.06).
Asked by Ujjwal Kumar | 06 Oct, 2010, 10:26: AM
Expert Answer
|
symbol |
weight |
Molecular weight |
moles |
Ratios of moles |
Simplest whole no. ratio |
|
Fe |
7.30 |
55.55 |
7.30/55.55=.1314 |
.1314/.1314=1 |
2 |
|
S |
6.30 |
32.06 |
6.30/32.06=.196 |
.196/.1314=1.5 |
3 |
Hence, empirical formula is Fe2S3
Answered by | 06 Oct, 2010, 07:41: PM
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