Calculate the emperical formula of the compound formed when 7.30 g of iron powder reacts completely with 6.30 g of powdered sulphur . (At mass Fe=55.55;S=32.06).

Asked by Ujjwal Kumar | 6th Oct, 2010, 10:26: AM

Expert Answer:

symbol

weight

Molecular weight

moles

Ratios of moles

Simplest whole no. ratio

Fe

7.30

55.55

7.30/55.55=.1314

.1314/.1314=1

2

S

6.30

32.06

6.30/32.06=.196

.196/.1314=1.5

3

 Hence, empirical formula is Fe2S

Answered by  | 6th Oct, 2010, 07:41: PM

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