CBSE Class 12-science Answered
calculate the density of silver which crystallises in the fcc structure the distance between the nearest silver atoms in this structure is 287pm
Asked by Akshaya Parthasarathy | 02 Jul, 2011, 12:00: AM
Expert Answer
For fcc a= 1.414 d where d= distance between the nearest silver atoms
a= (1.414 x 287) pm
a= 405.8 pm =405.8 x 10-10 cm
Also for fcc z=4
d = (Z X M) /(a3 x NA)
= 4 X107.87 /[(405.8 X10-10)3 X6.022X 1023]
= 10.73 g cm-3
Answered by | 04 Jul, 2011, 10:19: AM
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