Calculate the density of silver which crystallises in the FCC structure. The distance b/w the nearest silver atom in this structure is 287pm.

Asked by Anushri | 24th Jun, 2013, 04:19: PM

Expert Answer:

Nearest neighbour in fcc crystal = 1/2 x face diagonal  =   1/2 (?2a ). 
or 287 = a / ? 2  .
or a = 287 x 1.414 = 4.05 pm.
Volume a 3 = (4.05)3 pm..... convert it into cm3  .
now, d = Z  M   / a3  N  
Z for fcc structure is = 4
mass for Silver = 108.
N = 6.O2 X 10  23   

Answered by  | 25th Jun, 2013, 01:25: AM

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