Reading shown by ammeter

Electoral power between P and Q

Asked by lovemaan5500 | 4th Jan, 2018, 07:45: PM

Expert Answer:

emf of each cell is 2 V. Hence potential difference across the battery is 2×2 = 4V. There are two resistors of resistance 4Ω each connected in parallel. Hence equivalenet resistance is 2Ω. Hence current in the circuit as shown by ammeter is 4 / 2 = 2A.
Electrical power across P and Q is i2×R = 2×2×2 = 8 W

Answered by  | 4th Jan, 2018, 07:59: PM

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