CALCULATE  POTENTIAL  OF  HYDROGEN  ELECTRODE IN  CONTACT  WITH  A  SOLUTION  OF  PH 10

Asked by pardeepkumar2281 | 26th Sep, 2018, 09:00: PM

Expert Answer:

Given:
 
pH = 10
 
We know,
 
pH = -log[H+]
 
10 = -log[H+]
 
[H+] = -antilog(10)
 
[H+] = 10-10 M
 
straight E subscript cell space equals space straight E to the power of ring operator space minus fraction numerator 0.0591 over denominator 1 end fraction log space fraction numerator left square bracket straight H subscript 2 right square bracket over denominator open square brackets straight H to the power of plus close square brackets end fraction

straight E to the power of ring operator space equals space 0

straight E subscript cell space equals space 0 space minus fraction numerator 0.0591 over denominator 1 end fraction log space open parentheses 1 over 10 to the power of negative 10 end exponent close parentheses

straight E subscript cell space equals space minus fraction numerator 0.0591 over denominator 1 end fraction cross times 10

straight E subscript cell space equals space minus 0.591 space straight V
 
The potential of the hydrogen electrode is -0.591 V

Answered by Varsha | 27th Sep, 2018, 11:26: AM