Calculate cell potential for the following cell:
Asked by Ujjwal Kumar
| 22nd Sep, 2010,
06:28: PM
Expert Answer:
Eocell= 1.358 - (- 0.13) = 1.488 V
E = Eo - .059/ n log [Pb+2]/ [Cl-]2
= 1.488 - .059/ 2 log 1* 10 -3/ (.1)2
= 1.488 -.059/2 *.1
=1.488 -.00295
= 1.485 V
Answered by
| 23rd Sep, 2010,
01:35: AM
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