Calculate cell potential for the following cell:

Asked by Ujjwal Kumar | 22nd Sep, 2010, 06:28: PM

Expert Answer:

Eocell= 1.358 - (- 0.13) = 1.488 V
 
E = Eo - .059/ n log [Pb+2]/ [Cl-]2
  = 1.488 - .059/ 2 log  1* 10 -3/ (.1)2
 = 1.488 -.059/2 *.1
=1.488 -.00295
= 1.485 V

Answered by  | 23rd Sep, 2010, 01:35: AM

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