calcium carbonate reacts with aq HCL to give CaCl2 & CO2 according to the reaction given below : CaCo3+2HCL(aq)+CO2+H2O what mass of CaCl2 will be formed whin 250ml of 0.76M HCL react with 1000g of CaCo3? name the limiting reagent. calculate the no. of moles of CaCl2 formed in the reaction.

Asked by shivani sharma | 28th Aug, 2012, 06:05: PM

Expert Answer:

Now, according to the definition of molarity, the no. of moles are calculated for 1000 ml or 1 litre of the solution.

1000 ml of 0.75 M HCl contains HCl = 0.75 mol

So, 25 ml of 0.75 M HCl will contain HCl = 0.75x25/1000 = 0.01875 mol

2 mol of HCl reacts with = 1 mol of CaCO3

So, 0.01875 mol of HCl will react with = 1x0.01875/2 = 0.009375 mol

Molar mass of CaCO3 = 100 g

Hence, the mass of 0.009375 mol of CaCO3 = no. of moles x molar mass

                                                               = 0.009375 x 100 = 0.9375 g

Answered by  | 31st Aug, 2012, 05:32: PM

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