by using remainder theorem

Asked by Nidhi Munshi | 29th May, 2013, 10:34: PM

Expert Answer:

When f(x) = x^3+2x^2+Kx+3 is divided by g(x) = x-3 , the remainder is 21
 
By remainder theorem
Remainder = f(3)
21 = (3)^3+2(3)^2+K(3)+3
21 = 27 + 18+3K +3
21 = 48 + 3K
3K = -27
K = -9

Answered by  | 30th May, 2013, 02:56: AM

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