CBSE Class 11-science Answered
Bond Order
Asked by Ishaan Kumar | 18 Feb, 2011, 08:10: PM
Expert Answer
Dear Student
bond order = ½ (bonding electrons − antibonding electrons)
BO of N2 = 1/2(8-2)= 3
O2: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)1(p*2py)1
Bond Order = 1/2(8-4)= 2
O2+: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)2 (p*2py)
Bond Order = 1/2(8-3) = 2.5
O2-: KK(s2s)2 (s*2s)2 (s2pz)2 (p2px)2 (p2py)2 (p*2px)2 (p*2py)1
Bond Order = 1/2 (8-5) =1.5
We hope that clarifies your query.
Regards
Team
Topperlearning
Answered by | 18 Feb, 2011, 09:07: PM
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