Bond angle in PH4+>PH3. why?

Asked by viveksureshkumar | 2nd Dec, 2010, 11:26: PM

Expert Answer:

In PH3, P is sp3 hybridized. Three orbitals are involved in bonding with three hydrogen atoms and the fourth one contains a lone pair. As lone pair-bond pair repulsion is stronger than bond pair-bond pair repulsion, the tetrahedral shape associated with sp3 bonding is changed to pyramidal. PH3 combines with a proton to form in which the lone pair is absent. Due to the absence of lone pair in, there is no lone pair-bond pair repulsion. Hence, the bond angle in is higher than the bond angle in PH3.

 

Answered by  | 3rd Dec, 2010, 12:24: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.