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CBSE Class 11-science Answered

based on motion under gravity
Asked by | 03 Dec, 2008, 03:34: PM
answered-by-expert Expert Answer

Let the height of tower be h.

We have:

h=1/2gt2

and h-20=1/2g(t-1)2

solving:

20=1/2g(2t-1)

hence ,t=20/g+ 1

and h=1/2g(20/g+1)2

 

Answered by | 04 Dec, 2008, 12:10: PM
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