CBSE Class 11-science Answered
based on motion under gravity
Asked by | 03 Dec, 2008, 03:34: PM
Expert Answer
Let the height of tower be h.
We have:
h=1/2gt2
and h-20=1/2g(t-1)2
solving:
20=1/2g(2t-1)
hence ,t=20/g+ 1
and h=1/2g(20/g+1)2
Answered by | 04 Dec, 2008, 12:10: PM
Concept Videos
CBSE 11-science - Physics
Asked by pranavsrinivas82 | 08 Jan, 2024, 11:30: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rame123shshiv | 14 Nov, 2023, 06:18: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kfcispuppy | 30 Sep, 2023, 10:06: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sakethrockzz007 | 14 Aug, 2023, 04:30: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sahuaryanbro1.0 | 01 Jan, 2023, 10:17: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by subhankarnanda123 | 20 Dec, 2022, 08:36: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kashyspalbert91 | 11 Mar, 2022, 04:11: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by alkrishna4652 | 24 Feb, 2022, 01:46: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shreyamishra270304 | 04 Aug, 2021, 08:32: AM
ANSWERED BY EXPERT