Bar mangnet bent into a semicircle
Asked by | 3rd Sep, 2008, 04:03: PM
L- be the length of the bar magnet which now is bent into a semi circle.
m- pole strength
M- original magnetic moment
M' - the new magnetic moment
r - radius of the semicircle that has been made.
M = m x L
The distance between the poles now becomes 2r from L(earlier) .
Also L= r (beacuse the length is now the circumference of the semi circle)
That gives r = L/
Hence, M' = m x 2 r = mx 2 (L / ) = (2/) M
Answered by | 20th Oct, 2008, 02:56: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number